00:01
And to be able to do this, we need to know that a liu acid is going to be an electron -pair acceptor, where a base is going to be an electron -pair donor.
00:21
All right.
00:22
So in the first equation, we have h -n -o -2 plus o -h -minus goes to an o2 -mine plus h -2 -o.
00:31
So the first thing that sticks out to me is that we have this o -h going to h -2 -o.
00:36
And so for this to happen, we have to accept a hydrogen.
00:42
And so what's happening is that this electron that's up here is donating its electron to pull off a hydrogen.
00:48
So this is going to be the base.
00:51
Also, we can see that we have the hno2 here, and it's losing the hydrogen from accepting the electrons from the oh.
01:04
So this is going to be your acid.
01:08
Our next equation is f .e.
01:11
Br3 plus br minus, and it's going to form f .e .b .r...