Mathematically, this can be expressed as:
\[ \frac{r_{N2O4}}{r_{NO}} = \sqrt{\frac{M_{NO}}{M_{N2O4}}} \]
where \(r_{N2O4}\) and \(r_{NO}\) are the rates of effusion of \(N2O4\) and \(NO\) respectively, and \(M_{NO}\) and \(M_{N2O4}\) are their molar masses.
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