Question
If $1, \log _{3}\left(3^{x}-2\right), 2 \log _{9}\left(3^{r}-8 / 3\right)$ are in A.P., thevalue of $x$ can be(a) $\log \left(\frac{4}{3}\right)$(b) $\frac{\log 4}{\log 3}$(c) 1(d) $\log _{3} 4$
Step 1
P., we can use the property of A.P. which states that the second term minus the first term equals the third term minus the second term. This gives us the equation: \[\log _{3}\left(3^{x}-2\right) - 1 = 2 \log _{9}\left(3^{r}-8 / 3\right) - \log Show more…
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