Question
If $3^{x}=4^{x-1}$, then $x=$(a) $\frac{2 \log _{3} 2}{2 \log _{3} 2-1}$(b) $\frac{2}{2-\log _{2} 3}$(c) $\frac{1}{1-\log _{4} 3}$(d) $\frac{2 \log _{2} 3}{2 \log _{2} 3-1}$
Step 1
We can rewrite 4 as $2^{2}$, so the equation becomes $3^{x}=2^{2(x-1)}$. Show more…
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