Question
If $(10)^{9}+2(11)^{1}(10)^{8}+3(11)^{2}(10)^{7}+\ldots .+10(11)^{9}$$=k(10)^{9}$ then $k$ is equal to $\quad$ [2014](A) $\frac{121}{10}$(B) $\frac{441}{100}$(C) 100(D) 110
Step 1
\] This can be rewritten in summation notation as: \[ \sum_{n=0}^{9} (n+1)(11^n)(10^{9-n}). \] Show more…
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