If 30.0 mL of 0.150 M CaCl2 is added to 15.0 mL of 0.100 M AgNO3, what is the mass in grams of A

If 30.0 mL of 0.150 M CaCl2 is added to 15.0 mL of 0.100 M...

Key Concepts

Molarity and Volume Relationships

Molarity is a measure of the concentration of a solution, defined as the number of moles of solute per liter of solution. Understanding the relationship between moles, volume, and molarity is essential for calculating how many moles of each reactant are present in a given volume of solution, which is crucial for quantitative chemical analysis.

Limiting Reactant Determination

In a chemical reaction, the limiting reactant is the substance that is completely consumed first, governing the maximum amount of product that can be formed. Identifying the limiting reactant involves comparing the mole ratios of the reactants as determined by the balanced chemical equation.

Stoichiometry of Chemical Reactions

Stoichiometry involves using the balanced chemical equation to relate the moles of reactants to the moles of products. This concept is critical for calculating the theoretical yield of a product in a reaction based on the initial amounts of reactants.

Precipitation Reactions

Precipitation reactions occur when two aqueous solutions combine and form an insoluble solid, known as the precipitate. Recognizing the formation of a precipitate and understanding solubility rules are key to predicting and quantifying the outcome of such reactions.

Transcript

00:01 Okay, question 81, question 81 give us two set of solutions, 30mmm of calcium loride .1 .15m, and another one 15m of silver nitrate .1m.

00:15 And we need to find the mass of silver lauride reciprocate.

00:23 And before we do this of reaction, we have to find which one is limiting reaction.

00:31 And i suggest you guys should conclude the more of the substance first because we started write down equation.

00:38 Okay? we remember what this formula? m equal n over v.

00:44 So n should be equal mv based on this formula we can calculate calcium chloride and silver nitrate.

00:52 Remember you have to convert a milliliter to liter before we do it.

00:57 Why? because molarity is more over a liter, not more of a milliliter.

01:02 And after we calculate this, we get the more of calcium chloride amount and the amount of silver nitrate.

01:12 Then we write equation.

01:14 We write equation so we had to find the more ratio of the substance in the equation.

01:19 From this more ratio, we should find which one is limiting reactor.

01:25 And you can tell here, if we have two more of silver nitrate, we will get only one more calcium chloride.

01:31 And now if we have 1 .5 times 10 negative 3, more of silver nitrate, so we only get 7 .5 times 10 negative 4 calcium chloride.

01:44 So this is the limiting.

01:47 So that's why because calcium chloride react integration less than the amount of calcium chloride they give us.

01:57 So calcium chloride is a set reaction and silver nitrate...

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