00:01
The reaction equation in this question is based on the same reaction equation that we had in the previous question.
00:10
Now, during this reaction, 5 mils of hydrogen gas reacts with 0 .15 moles of oxygen gas in order to produce a certain amount of water.
00:21
We need to identify the limiting reactant here and also calculate the number of moles of water that can form.
00:30
During this reaction.
00:33
For this purpose, we will look at two different situations in order to identify the limiting reactant first.
00:41
And that is, firstly, we will look at the number of moles of water that can be produced if we start off with 5 moles of hydrogen gas.
00:53
And secondly, we will look at the number of moles of water that can be produced when starting off with 0 .15 0 moles of oxygen gas.
01:04
We will then compare these two situations in order to identify the limiting reactant.
01:10
So firstly, in order to determine the number of moles of water that can form when starting off with 5 moles of hydrogen gas, we need to work with the mole ratio of water to hydrogen gas.
01:26
So for this purpose, we will have a look at the stoichiometric coefficients here.
01:32
For water it is 2.
01:34
For hydrogen gas it is 2.
01:36
So that mole ratio of water over hydrogen gas is 2 over 2.
01:46
We can therefore say that the number of moles of water that can form in this case will be 1 times the number of moles of water.
01:56
Hydrogen gas and this is equal to 1 times 5 moles which is just equal to 5 moles...