Question
If $a \neq 0, a \neq 1$ and$\left|\begin{array}{ccc}x+1 & x & x \\ x & x+a & x \\ x & x & x+a^{2}\end{array}\right|=a^{3}+f(x) \cdot a\left(a^{2}+a+1\right)$, then(A) $f(x)=x$(B) $f(x)=x^{2}$(C) $f(x)=x^{3}$(D) None of these
Step 1
We can simplify this determinant by performing the operation of multiplying the first column by -1 and adding it to the third column. This gives us the matrix: $\left|\begin{array}{ccc}x+1 & x & x \\ x & x+a & x \\ x & x & x+a^{2}-a\end{array}\right|$ Show more…
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