If a particle with mass $ m $ moves with position vector $ r(t) $, then its angular momentum is defined as $ L(t) = m r(t) \times v(t) $ and its torque as $ \tau (t) = m r(t) \times a(t) $. Show that $ L^\prime (t) = \tau (t) $. Deduce that if $ \tau (t) = 0 $ for all $ t $, then $ L(t) $ is constant. (This is the law of conservation of angular momentum.)