Question
If a vector $2 \hat{i}+3 \hat{j}+8 \hat{k}$ is perpendicular to the vector $4 \hat{j}-4 \hat{i}+\alpha \hat{k}$ then the value of $\alpha$ is(A) $\frac{1}{2}$(B) $\frac{-1}{2}$(C) 1(D) $-1$
Step 1
Step 1: Given two vectors $\vec{A} = 2 \hat{i}+3 \hat{j}+8 \hat{k}$ and $\vec{B} = 4 \hat{i}-4 \hat{j}+\alpha \hat{k}$ are perpendicular to each other. Show more…
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