00:02
I'm going to do this problem algebraically using the distributive property, but you could instead do it numerically.
00:10
You could choose numbers for x, for y, and for c, and then just follow order of operations with those numbers.
00:16
Okay, so what we're going to do is subtract b from a.
00:18
So here's a, 2x minus the quantity y minus 2c, and we're subtracting b.
00:24
I'm going to put brackets around b, 2x minus y, minus c.
00:30
Okay, so the first thing i want to do is distribute the negative, that i see here and also distribute the negative sign here.
00:38
And just so you know, the parentheses that we see inside the brackets, these parentheses around the 2x minus y, they're not actually doing anything.
00:46
So we have 2x minus y plus 2c from distributing the negative, minus 2x plus y from distributing the negative plus c.
01:00
Whoops, that should say 2c there.
01:03
So plus 2c.
01:04
Let's just fix that...