Question
If $ \displaystyle \int^9_0 f(x) \, dx = 37 $ and $ \displaystyle \int^9_0 g(x) \, dx = 16 $, find $$ \int^9_0 \bigl[ 2f(x) + 3g(x) \bigr] \, dx $$
Step 1
Step 1: Use linearity of integrals: ∫_0^9 [2f(x)+3g(x)] dx = 2∫_0^9 f(x) dx + 3∫_0^9 g(x) dx. Show more…
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If $\int_{0}^{9} f(x) d x=37$ and $\int_{0}^{9} g(x) d x=16,$ find $\int_{0}^{9}[2 f(x)+3 g(x)] d x$
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The Definite Integral
$\begin{array}{l}{\text { If } \int_{0}^{9} f(x) d x=37 \text { and } \int_{0}^{9} g(x) d x=16, \text { find }} \\ {\int_{0}^{9}[2 f(x)+3 g(x)] d x}\end{array}$
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If 9 0 f(x) dx = 31 and 9 0 g(x) dx = 18, find 9 0 [2f(x) + 3g(x)] dx.?
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