Question
If $f$ and $g$ are differentiable functions such that $g^{\prime}(a)=2$ and $g(a)=b$ and if $f o g$ is an identity function, then $f^{\prime}(b)$ has the value equal to(a) $2 / 3$(b) 1(c) 0(d) $1 / 2$
Step 1
Now, we differentiate both sides with respect to $x$ using the chain rule: $\frac{d}{dx}(f(g(x))) = \frac{d}{dx}(x)$ $f'(g(x)) \cdot g'(x) = 1$ Show more…
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The Product and Quotient Rules
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