Question
If $\frac{\log _{2}\left(4 x^{2}-x-1\right)}{\log _{2}\left(x^{2}+1\right)}>1$ then $x$ lies in the interval(a) $(-\infty,-2 / 3)$(b) $(1, \infty)$(c) $(-2 / 3,0)$(d) none of these
Step 1
We can interpret this as $\log _{2}\left(4 x^{2}-x-1\right) > \log _{2}\left(x^{2}+1\right)$. Show more…
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