Question
If $f(x)=x^{2} \log x \operatorname{on}[1, e]$ then $\log$ (greatest of $f(x)$- Least of $f(x))$ is equal to
Step 1
The derivative of the function, $f'(x)$, can be found using the product rule and the chain rule. The derivative is given by: \[f'(x) = 2x\log x + x\] This derivative never equals zero in the interval $[1, e]$. Show more…
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