Question
If $m={ }^{n} C_{2}$, then prove that ${ }^{m} C_{2}=3 .{ }^{n+1} C_{4}$.If $m={ }^{n} C_{2}$, then prove that ${ }^{m} C_{2}=3 .{ }^{n+1} C_{4}$.
Step 1
We can write this as $m = \frac{n(n-1)}{2}$. Show more…
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