Now, we are given that ${n \choose 3} + {n \choose 16} = {n \choose 23}$. Using the definition of the binomial coefficient, we can rewrite this equation as:
$\frac{n!}{3!(n-3)!} + \frac{n!}{16!(n-16)!} = \frac{n!}{23!(n-23)!}$.
Notice that $n!$ is a common
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