Question
If $P$ is any point on the ellipse $4 x^{2}+16 y^{2}=64$ whose foci are $S$ and $S^{1}$, then $S P+S^{1} P$ is(a) 4(b) 8(c) 12(d) 16
Step 1
We can rewrite this equation by dividing each term by 64 to get $\frac{x^{2}}{16}+\frac{y^{2}}{4}=1$. Show more…
Show all steps
Your feedback will help us improve your experience
Goutam Chand and 89 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If $(x-4)^{2}+4(y-3)^{2}=16$ is graphed, the sum of the distances from any fixed point on the curve to the two foci is (A) 4 (B) 8 (C) 12 (D) 16 (E) 32
Find the foci for each equation of an ellipse. $$ 16 x^{2}+4 y^{2}=64 $$
Quadratic Relations And Conic Sections
Ellipses
If the foci of an ellipse are (-4,4) and $(6,4),$ then the coordinates of the center of the ellipse are __________. (a) (1,4) (b) (4,1) (c) (1,0) (d) (5,4)
Analytic Geometry
The Ellipse
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD