Question
If $p+q+r=0=a+b+c$, then the value of the deter$\operatorname{minant}\left|\begin{array}{ccc}p a & q b & n c \\ q c & n a & p b \\ r b & p c & q a\end{array}\right|$ is(A) 0(B) $p q+q b+r c$(C) 1(D) None of these
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We want to find the value of the determinant of the matrix $\left|\begin{array}{ccc}p a & q b & r c \\ q c & n a & p b \\ r b & p c & q a\end{array}\right|$. Show more…
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If $\frac{1}{a}, \frac{1}{b}$ and $\frac{1}{c}$ are respectively the $p^{\text {th }}, q^{\text {th }}$ and $r^{\text {th }}$ terms of an A.P., then the value of the determinant $\left|\begin{array}{ccc}{ }^{8} C_{3} & { }^{9} C_{5} & { }^{10} C_{7} \\ { }^{8} C_{4} & { }^{9} C_{6} & { }^{10} C_{8} \\ { }^{9} C_{n} & { }^{10} C_{n+2} & { }^{11} C_{n+4}\end{array}\right|$ is (A) $a b c$ (B) $p q r$ (C) 0 (D) None of these
$\begin{aligned}&\text { The value of the determinant } \\&\begin{array}{llll}a & b-c & c+b \\ \text { (A) } a^{2}+b^{2}+c^{2}\end{array} & \begin{array}{ccc}a & b & c-a \\ a-b & a+b & c\end{array} \mid \text { is }\end{aligned}$ (B) $a b c(a+b+c)$ (C) $\left(a^{2}+b^{2}+c^{2}\right)(a+b+c)$ (D) None of these
Value of the determinant $\left|\begin{array}{ccc|}a+2 b+3 c & 2 a+3 b+4 c & 3 a+4 b+5 c \\ p-q+r & p+2 r & p+q+3 r \\ 2 a+3 b & 4 a+5 b & 6 a+7 b\end{array}\right|$ is equal to (a) $(a+b+c)$ (b) $(a+b+c)^{2}$ (c) 0 (d) $(p+q+r)^{2}$
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