Question
If $\sqrt{y+x}+\sqrt{y-x}=c$ (where $c \neq 0$ ), then $\frac{d y}{d x}$ has the value equal to(a) $\frac{2 x}{c^{2}}$(b) $\frac{x}{y+\sqrt{y^{2}-x^{2}}}$(c) $\frac{y-\sqrt{y^{2}-x^{2}}}{x}$(d) $\frac{c^{2}}{2 y}$
Step 1
Step 1: Start with the given equation: \[ \sqrt{y+x} + \sqrt{y-x} = c \] Show more…
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