Question
If the angle between the vectors $\vec{A}$ and $\vec{B}$ is $\theta$, the value of the product $(\vec{B} \times \vec{A}) \cdot \vec{A}$ is equal to(A) $B A^{2} \cos \theta$(B) $B A^{2} \sin \theta$(C) $B A^{2} \sin \theta \cos \theta$(D) Zero
Step 1
Step 1: The cross product of two vectors $\vec{B}$ and $\vec{A}$ is given by $\vec{B} \times \vec{A} = -\vec{A} \times \vec{B} = -BA \sin \theta \hat{n}$, where $\hat{n}$ is a unit vector perpendicular to both $\vec{A}$ and $\vec{B}$. Show more…
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Section B
The angle between the vectors $\vec{A}$ and $\vec{B}$ is $\theta$. The value of the triple product $\vec{A} \cdot(\vec{B} \times \vec{A})$ is (a) $A^{2} B$ (b) \%ero (c) $A^{2} B \sin \theta$ (d) $A^{2} B \cos \theta$
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