Question
If the fractional part of the number $\frac{2^{403}}{15}$ is $\frac{k}{15}$, then $\mathrm{k}$ is equal to:(a) 6(b) 8(c) 4(d) 14
Step 1
This is equivalent to $2^{100} \cdot 16^2 \cdot 2$, which is $8 \cdot (16^{100})$. Show more…
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