Question
If the function $f(x)$ defined as $f(x)=\left\{\begin{array}{c}3 \quad, x=0 \\ \left(1+\frac{a x+b x^{3}}{x^{2}}\right)^{1 / x}, & x>0\end{array}\right.$is continuous at $x=0$, then(A) $a=0$(B) $b=e^{3}$(C) $a=1$(D) $b=\ln 3$
Step 1
This means that the limit of the function as $x$ approaches $0$ from the right is equal to the value of the function at $x=0$. So, we have: \[\lim_{{x \to 0^+}} f(x) = f(0)\] Show more…
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