Question
If the interatomic spacing in a steel wire is $3 \AA \&$ $\mathrm{Y}_{\text {Steel }}=20 \times 10^{10}\left(\mathrm{~N} / \mathrm{m}^{2}\right) .$ The force constant $=\ldots \ldots \ldots .$(A) $6 \times 10^{-2}(\mathrm{~N} / \AA)$(B) $6 \times 10^{-9}(\mathrm{~N} / \AA)$(C) $6 \times 10^{-5}(\mathrm{~N} / \AA)$(D) $6 \times 10^{-5}(\mathrm{~N} / \AA)$
Step 1
Step 1: Given that the interatomic spacing in a steel wire is $3 \AA$ and Young's modulus $Y_{\text {Steel }}=20 \times 10^{10}\left(\mathrm{~N} / \mathrm{m}^{2}\right)$, we need to find the force constant. Show more…
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