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If the magnitude of the magnetic force on a proton is $F$ when it is moving at $15.0^{\circ}$ with respect to the field, what is the magnitude of the force (in terms of $F$ ) when this charge is moving at $30.0^{\circ}$ with respect to the field?
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Physics 101 Mechanics
Physics 102 Electricity and Magnetism
Chapter 20
Magnetic Field and Magnetic Force
Motion Along a Straight Line
Motion in 2d or 3d
Electric Charge and Electric Field
Gauss's Law
Current, Resistance, and Electromotive Force
Direct-Current Circuits
Magnetic Field and Magnetic Forces
Sources of Magnetic field
Electromagnetic Induction
Inductance
Cornell University
Rutgers, The State University of New Jersey
University of Washington
University of Winnipeg
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So we know that the magnetic force on a charged particle is going to be equal to the absolute value of the charge times the velocity of the charge times the magnitude of the magnetic field time sign. If I We know that at this point the force is going to be directly proportional to the sign of five s so we can say that f divided by F prime He's going to be equal to sign of fire divided by sign of five prime. We know that we can solve for F prime and say I have prime is going to be ableto f time's sign of five prime divided by sign of fire. And this is going to be equal Teo F. Sign of 30 degrees divided by sign of 15 degrees. So we can say that force final is going to be equal to 1.93 times force and national. That would be our final answer. That is the end of the solution. Thank you for watching
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