If the system of equations $a x+b y+c=0, b x+c y+a$ $=0, c x+a y+b=0$ has a solution then the system of equations $(b+c) x+(c+a) y+(a+b) z=0$
$(c+a) x+(a+b) y+(b+c) z=0$
$(a+b) x+(b+c) y+(c+a) z=0$ has
(A) only one solution
(B) no solution
(C) infinite number of solutions
(D) None of these