Question
If two antinodes and three nodes are formed in a distance of $1.21 \AA$, then the wavelength of the stationary wave is(A) $2.42 \AA$(B) $6.05 \AA$(C) $3.63 \AA$(D) $1.21 \AA$
Step 1
Step 1: We know that the distance between two nodes or two antinodes is half the wavelength (λ/2). Show more…
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