If $\vec{A}-A_{x} \hat{i}+A_{v} \hat{j}+A_{z} \vec{k}, \vec{B}-B_{x} \hat{i}+B_{y} \hat{j}+B \dot{k}$ we have
Column-1 Column-II
(a) $\vec{A} \cdot \vec{B}$
(p) $A_{x}=B_{x^{\prime}}, A_{y}=B_{y} A_{z}=B_{z}$
(b) $\vec{A}-\vec{B}$
(q) $\vec{A} \cdot \vec{B}=0$
(c) $\vec{A} \uparrow \uparrow \vec{B}$
(r) $A_{\pi} B_{x}+A_{y} B_{r}+A_{z} B_{z}$
(d) $\vec{A} \perp \vec{B}$
(s) $\sqrt{\left(A_{x}^{2}\left|A_{y}^{2}\right| A_{z}^{2}\right)\left(B_{x}^{2}\left|B_{y}^{2}\right| B_{z}^{2}\right)}$