Question
If $\vec{b}=3 \hat{i}+4 \hat{j}$ and $\vec{a}=\hat{i}-\hat{j}$, the vector having the same magnitude as that of $\vec{b}$ and parallel to $\vec{a}$ is(A) $\frac{5}{\sqrt{2}}(\hat{i}-\hat{j})$(B) $\frac{5}{\sqrt{2}}(\hat{i}+\hat{j})$(C) $5(\hat{i}-\hat{j})$(D) $5(\hat{i}+\hat{j})$
Step 1
The magnitude of a vector is given by the formula $\sqrt{x^2 + y^2}$, where $x$ and $y$ are the components of the vector. So, the magnitude of $\vec{b}$ is $\sqrt{3^2 + 4^2} = 5$. Show more…
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Practice Test 3
Section 1
Transcript
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