Question
If $z_{1}=12\left(\cos 125^{\circ}+j \sin 125^{\circ}\right)$ and $z_{2}=3\left(\cos 72^{\circ}+j \sin 72^{\circ}\right)$, find (a) $z_{1} z_{2}$ and (b) $\frac{z_{1}}{z_{2}}$ giving the results in polar form.
Step 1
So, we can apply this formula to find $z_{1}z_{2}$. Show more…
Show all steps
Your feedback will help us improve your experience
M Hassan Anwar and 71 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If $z_{1}=12\left(\cos 125^{*}+j \sin 125^{\prime}\right)$ and $z_{2}=3\left(\cos 72^{\circ}+j \sin 72^{*}\right)$, find (a) $z_{1} z_{2}$ and (b) $\frac{z_{1}}{z_{2}}$ giving the results in polar form.
Complex numbers 2
Test exercise
$49-56$ me product $z_{1} z_{2}$ and the quotient $z_{1} / z_{2}$ . Express your answer in polar form. $$ \begin{array}{l}{z_{1}=4\left(\cos 120^{\circ}+i \sin 120^{\circ}\right)} \\ {z_{2}=2\left(\cos 30^{\circ}+i \sin 30^{\circ}\right)}\end{array} $$
Polar Coordinates and Vectors
Polar Form of Complex Numbers; DeMoivre’s Theorem
If $z=2\left(\cos 25^{\circ}+j \sin 25^{\circ}\right)$, find $z^{3}$ in polar form.
Test exercise F.2
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD