Question
(II) A 55-g bullet traveling at 250 m/s penetrates a block of ice at 0$^\circ$C and comes to rest within the ice. Assuming that the temperature of the bullet doesn't change appreciably, how much ice is melted as a result of the collision?
Step 1
The formula for kinetic energy is given by: \[ KE = \frac{1}{2} m v^2 \] where \( m \) is the mass of the bullet and \( v \) is the velocity of the bullet. Show more…
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(II) A 70 -g bullet traveling at 250 $\mathrm{m} / \mathrm{s}$ penetrates a block of ice at $0^{\circ} \mathrm{C}$ and comes to rest within the ice. Assuming that the temperature of the bullet doesn't change appreciably, how much ice is melted as a result of the collision?
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