00:01
The period of precision t is related to the reciprocal of the angular positional frequency by this.
00:11
And we will use equation 11 .13c for the precision angular velocity, which is capital omega here.
00:23
So from this equation, we have capital omega to be equal to mgr over i omega.
00:31
Now we can substitute this expression into this equation.
00:36
So we have t equal to m g 2 pi i omega over m g r.
00:51
And since the gyroscope has a disk shape, i will be equal to half times mass times radius of the gyroscope or radius of the disk square.
01:08
Now we have r of the axel is equal to half of the length of the axle.
01:25
So this will be equal to 0 .105 meter.
01:29
Make sure you write all the variables in standard units to be consistent with the equation, to be consistent with all the units.
01:41
So we plug this expression of i over here and we can also write omega to be equal to 2 pi times frequency.
01:56
And frequency is given to be 45 revolutions per second.
02:07
So doing that we get mgr.
02:28
Now we can simplify this expression a little bit...