(II) A transistor, whose current gain β= iC/iB = 65, is connected as in Fig. 29-41 with RB = 3.8

step 1 So the voltage gain, in this case, is given by the collected voltage over the base voltage. And

(II) A transistor, whose current gain β= iC/iB = 65, is...

(II) A transistor, whose current gain $\beta = i_C/i_B = 65$, is connected as in Fig. 29-41 with $R_B = 3.8 \mathrm{k}\Omega$ and $R_C = 7.8 \mathrm{k}\Omega$ Calculate ($a$) the voltage gain, and ($b$) the power amplification.

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Key Concepts

Transistor Current Gain (?)

Transistor current gain, typically denoted by ?, is the ratio of the collector current to the base current of a bipolar junction transistor. It indicates how effectively a small input current (at the base) is amplified to produce a larger output current (at the collector), and it is a fundamental parameter in analyzing and designing transistor amplifier circuits.

Voltage Gain

Voltage gain in an amplifier circuit is defined as the ratio of the output voltage to the input voltage. In transistor amplifiers, especially common-emitter configurations, the voltage gain is often determined by the circuit’s load resistors and the intrinsic properties of the transistor. It describes how much the circuit increases the amplitude of the input signal and is a crucial measure of an amplifier’s performance.

Power Amplification

Power amplification, or power gain, is the measure of how much the amplifier increases the power of the input signal. It is usually expressed as the ratio of the output power to the input power and is determined by both the voltage and current gains of the amplifier. This concept is important when assessing the efficiency and suitability of an amplifier for driving loads in practical applications.

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