Question
(II) A transistor, whose current gain $\beta=i_{C} / i_{B}=75,$ isconnected as in Fig. 43 with $R_{B}=3.8 \mathrm{k} \Omega$$R_{C}=7.8 \mathrm{k} \Omega$ . Calculate $(a)$ the voltage gain, and $(b)$ thepower amplification.
Step 1
Step 1: The voltage gain (A) of a transistor is given by the formula: \[A = \frac{V_{C}}{V_{B}}\] where \(V_{C}\) is the collector-emitter voltage and \(V_{B}\) is the base-emitter voltage. Show more…
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A transistor, whose current gain $\beta=i_{\mathrm{C}} / i_{\mathrm{B}}=75,$ is connected as in Fig. $40-43$ with $R_{\mathrm{B}}=3.8 \mathrm{k} \Omega$ and $R_{\mathrm{C}}=7.8 \mathrm{k} \Omega .$ Calculate $(a)$ the voltage gain, and $(b)$ the power amplification.
(II) A transistor, whose current gain $\beta = i_C/i_B = 65$, is connected as in Fig. 29-41 with $R_B = 3.8 \mathrm{k}\Omega$ and $R_C = 7.8 \mathrm{k}\Omega$ Calculate ($a$) the voltage gain, and ($b$) the power amplification.
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Transistors: Bipolar and MOSFETs
(II) Suppose that the current gain of the transistor in Fig. 43 is $\beta=i_{C} / i_{B}=85 .$ If $R_{C}=4.3 \mathrm{k} \Omega$ , calculate the ac output voltage for an ac input current of 2.0$\mu \mathrm{A} .$
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