00:01
A, what is the angle the shockwave makes with the direction of the airplane motion? and b, if the plane is flying at a height of 6 ,500 meters, how long after it is directly overhead will a shock wave? i wrote down what we were given here.
00:15
We're told that the speed of sound, which i write as v .s, is 310 meters per second, that the velocity of the airplane, which i write as v .p.
00:24
P is 2 .0 mach speed.
00:29
Okay, so that's two times the speed of sound.
00:31
So it's 2 .0 times v .s.
00:33
And the plane is flying at a height of 6 ,500 meters.
00:36
So for part a, we're asked to find the angle of the shock wave.
00:41
Well, we can use equation 16 -12 to find that, which says that the sign of the angle is equal to the ratio of the speed of sound to the speed of the object in question.
00:58
Which is in this case the plane so v .p right but v .p is 2 .0 times v.
01:08
Sub s so the v .s .s.
01:09
Is canceled so this is going to be 1 over 2 .0 okay so solve for theta we find that theta is equal to the inverse of the sign which can be written as sine to the minus 1 of 1 over 2 .0 okay so if you take the inverse of one half, you find that this is equal to 30 degrees.
01:48
Okay, so that's the solution for part a.
01:52
Now, for part b, we are asked to find the time it will take for a person to hear the shock wave after the plane flies directly overhead.
02:06
Okay, and we're told that the height of the plane is 6 ,500 meters.
02:10
So we can just draw out a little diagram here.
02:12
We have the, this is the direction to the ground.
02:20
It's the height of the plane.
02:23
This is velocity of the plane times the time...