00:01
We're asked to finger out how much sound energy is in one cubic centimeter of air in a region near the loudspeaker.
00:12
When the sound, when the sound level is at 120 decibels.
00:22
So we have a sound wave.
00:25
And so we need to figure out the intensity.
00:28
Now, we know that the indecibles, the intensity, the intensity, divided by the reference, the natural log of that times 10 is the sound intensity in decibels.
00:41
So we can invert that and get the sound intensity level is the reference times 10 to the beta in the sound intensity in decibels divided by 10.
00:57
This is 10 to the minus 12.
01:00
Beta was 120.
01:03
So this is 10 to the 12.
01:05
So that means we have.
01:05
Have one watt per meter squared.
01:08
So that means we have one watt of power.
01:12
We have this surface area is a meter squared.
01:15
We have one watt of sound power going through that area.
01:21
So that's kind of like a sound flux.
01:24
Now we want to figure out what the energy is.
01:28
Well, we know that this i is the power over going through the surface area.
01:37
So the power divided by the surface area.
01:39
And the power is delta e, delta t.
01:44
Okay...