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(II) Estimate the binding energy of the third electron in lithium using Bohr theory. [Hint: This electron has $n=2$ and "sees" a net charge of approximately $+1 e . ]$ The measured value is 5.36 $\mathrm{eV} .$
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This means that there are two electrons in the $1s$ orbital and one electron in the $2s$ orbital. Show more…
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(II) Estimate the binding energy of the third electron in lithium using the Bohr model. [$Hint$: This electron has $n =$ 2 and "sees" a net charge of approximately $+1e$ ] The measured value is 5.36 eV.
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If the outer electron in lithium moves in the $n=2$ Bohr orbit, the effective nuclear charge would be $Z_{\text {eff }} e=1 e,$ and the energy of the electron would be $-13.6 \mathrm{eV} / 2^{2}=-3.4 \mathrm{eV}$. However, the ionization energy of lithium is $5.39 \mathrm{eV},$ not $3.4 \mathrm{eV}$ Use this fact to calculate the effective nuclear charge $Z_{\text {eff }}$ seen by the outer electron in lithium. Assume that $r=4 a_{0}$ for the outer electron.
Energy of an electron in the second Bohr orbit is - 3.4 eV . Calculate the energy of an electron in the third Bohr orbit.
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