The formula for capacitors in series is given by:
\[ \frac{1}{C_{eq}} = \frac{1}{C_2} + \frac{1}{C_3} \]
Substituting the given values, we get:
\[ \frac{1}{C_{eq}} = \frac{1}{2C_3} + \frac{1}{C_3} = \frac{3}{2C_3} \]
Solving for $C_{eq}$, we get:
\[ C_{eq} =
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