Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

(II) The pressure variation in a sound wave is given by$\Delta P=0.0035 \sin (0.38 \pi x-1350 \pi t)$where $\Delta P$ is in pascals, $x$ in meters, and $t$ in seconds. Determine $(a)$ the wavelength, $(b)$ the frequency, $(c)$ the speed, and $(d)$ the displacement amplitude of the wave. Assume the density of the medium to be $\rho=2.3 \times 10^{3} \mathrm{kg} / \mathrm{m}^{3} .$

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

a) 5.3$m$b) 675$H z$c) 3600 $\mathrm{m} / \mathrm{s}$d) $1.0 \times 10^{-13} \mathrm{m}$

Physics 101 Mechanics

Chapter 16

Sound

Periodic Motion

Mechanical Waves

Sound and Hearing

University of Michigan - Ann Arbor

University of Washington

University of Winnipeg

Lectures

08:15

In physics, sound is a vibration that typically propagates as an audible wave of pressure, through a transmission medium such as a gas, liquid or solid. In human physiology and psychology, sound is the reception of such waves and their perception by the brain. Humans can only hear sound waves as distinct pitches when the frequency lies between about 20 Hz and 20 kHz. Sound above 20 kHz is known as ultrasound and has different physical properties from sound below 20 kHz. Sound waves below 20 Hz are called infrasound. Different species have different hearing ranges. In terms of frequency, the range of ultrasound, infrasound and other upper limits is called the ultrasound.

04:49

In physics, a traveling wave is a wave that propogates without a constant shape, but rather one that changes shape as it moves. In other words, its shape changes as a function of time.

05:06

The pressure variation in …

03:20

02:39

The pressure in a travelin…

03:50

As a sound wave travels t…

03:11

As a certain sound wave tr…

02:24

01:59

03:55

05:55

The pressure amplitude of …

03:35

(I) The pressure amplitude…

from the equation Off pressure variation sound wheels. From the question we can write, we can extract the delta s only delenda the revel in well, it will be equal to two pi work, eh? To party. Over. Okay, so the kay there we have these 0.38 So, to my word, Ok, which is a 0.38 Um, we just divide these two numbers. Then we have answer, which is 5.3 meters of land is 513 meters, but be were asked to find a frequency Quincy So the omega we have from the pressure equation that is given in question is Omega divided by two by, um, the no matter we are given, he's 13 50 13 50 over the constant to buy to buy. And if we do have these two numbers than answer here we get frequency is 6 75 hearts 6 75 hours. It hurts in party. We had asked to find a velocity of this room. So the last weekend right here being dumbs off omega or the web number K that is equal to Omega. We already have, which is 13 50 and the K is. Ah. Also, we have a jizo 0.38 from the question. So by dividing these two numbers, the last time you get here is three 3600 meters per second. I need your per second in body were asked to find there displacement amplitude so we can write displacement and resumed from the formula that be previously used. You know, our previous problem, the amplitude huge you can right here is a, um, Delta Pressure or to pie times the density off a medium times they've lost eating the medium times the frequency. Um, Janu pressure we have here is important. 0035 35 And then we can divide this by constant by times the domestic Ewan, the domestic even we have these 2300 2300 300 times the velocity, which is Ah three six under which we found it earlier. Sometimes times the frequency which is 6 75 6 75 which we found it up there. And by dividing these two numbers, the answer we get here for implicit ood Here is one times 10 to the power minus 13. So you in terms Tintin follow minus minus 13 regions End off the problem. Thank you for watching

View More Answers From This Book

Find Another Textbook

Rutgers, The State University of New Jersey

Simon Fraser University