00:01
Okay, so we're doing chapter 22, problem 49 here.
00:04
And this says charge is distributed within a solid sphere of radius r -not in such a way that the charge density is a function of the radial position.
00:16
So it's given as the charge density as a function of r is row not times r over r -not.
00:23
So if the total charge within the sphere is q and is positive, what is the electric field everywhere within the sphere in terms of? q, r0, and r.
00:36
Ok.
00:37
So first we know that the symmetry of the charge distribution allows this to be calculated using a gaussian spherical surface.
00:45
So for a radius of r less than r0, the enclosed charge is going to be the integral of our charge density function times dv.
01:02
So we can rewrite this in terms of just the radial distance because we know that the volume and row only depend on the radial distance.
01:13
So this now integrating from zero to r.
01:16
This is row not times r prime over r0 and dv when we're changing into dr, we pick up the 4 pi r squared, r squared, dr prime.
01:34
So this becomes our integral now to solve for what the enclosed charges and we can actually just solve for this.
01:41
So this becomes p -mat over r -not times 4 pi integral from 0 to r of r -pribue to r prime.
01:55
If we integrate that, we get row -not pi -r to the fourth over r -not.
02:02
So this is our charge enclosed as a function of r...