Question
(III) The specific heat per mole of potassium at low temperatures is given by $C_{V}=a T+b T^{3}, \quad$ where $a=2.08 \mathrm{mJ} / \mathrm{mol} \cdot \mathrm{K}^{2}$ and $b=2.57 \mathrm{mJ} / \mathrm{mol} \cdot \mathrm{K}^{4} .$ Determine (by integration) the entropy change of 0.15 $\mathrm{mol}$ of potassium when its temperature is lowered from 3.0 $\mathrm{K}$ to 1.0 $\mathrm{K}$ .
Step 1
Step 1: The change in entropy, $\Delta S$, is given by the formula $\Delta S = \int_{T1}^{T2} \frac{dQ}{T}$, where $dQ$ is the infinitesimal heat transferred to the system and $T$ is the temperature. Show more…
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