Question
In $1983,$ the United States began coining the one-cent piece out of copper-clad zinc rather than pure copper. The mass of the old copper penny is $3.083 \mathrm{g}$ and that of the new cent is 2.517 g. The density of copper is $8.920 \mathrm{g} / \mathrm{cm}^{3}$ and that of zinc is $7.133 \mathrm{g} / \mathrm{cm}^{3} .$ The new and old coins have the same volume. Calculate the percent of zinc (by volume) in the new cent.
Step 1
The formula for volume is given by: \[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \] For the old copper penny: \[ \text{Volume} = \frac{3.083 \, \text{g}}{8.920 \, \text{g/cm}^3} \] Show more…
Show all steps
Your feedback will help us improve your experience
Mayukh Banik and 79 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In 1983 , the United States began coining the cent piece out of copper-clad zinc rather than pure copper. The mass of the old copper penny is 3.083 g and that of the new cent is 2.517 g. Calculate the percent of zinc (by vol- ume) in the new cent. The density of copper is 8.960 $\mathrm{g} / \mathrm{cm}^{3}$ and that of zinc is $7.133 \mathrm{g} / \mathrm{cm}^{3} .$ The new and old coins have the same volume.
In 1983, the United States began coining the one-cent piece out of copper-clad zinc rather than pure copper. The mass of the old copper penny is 3.083 g and that of the new cent is 2.517 g. The density of copper is 8.920 g/cm3 and that of zinc is 7.133 g/cm3. The new and old coins have the same volume. Calculate the percent of zinc (by volume) in the new cent.
In $1983,$ the United States began coining the cent piece out of copper-clad rinc rather than pure copper. The mass of the old copper penny is $3.083 \mathrm{g},$ while that of the new cent is 2.517 g. Calculate the percentage of sinc (by volume) in the new cent. The density of copper is $8.960 \mathrm{g} / \mathrm{cm}^{3}$ and that of zinc is $7.133 \mathrm{g} / \mathrm{cm}^{3} .$ The new and old coins have the same volume.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD