In a 100 -m race, the winner is timed at 11.2 s. The...

Name: Problem 112, Chapter 3: University Physics Volume 1
Uploaded: 2020-07-01T12:18:21-08:00
Duration: 2 min 53 s
Channel: Surjit Tewari
Description: In a 100 -m race, the winner is timed at 11.2 s. The second-place finisher's time is 11.6 s. How far is the second-place finisher behind the winner when she crosses the finish line? Assume the velocity of each runner is constant throughout the race.

In a 100 -m race, the winner is timed at 11.2 s. The second-place finisher's time is 11.6 s. How far is the second-place finisher behind the winner when she crosses the finish line? Assume the velocity of each runner is constant throughout the race.

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Key Concepts

Proportional Reasoning in Relative Performance

By comparing the finish times of both athletes under the assumption of constant speed, proportional reasoning helps determine the distance covered by the runner lagging behind. The difference in finish times is used to calculate the extra distance the leading athlete covers, leading to the gap between the competitors.

Time, Speed, and Distance Relationship

The key equation d = vt (distance = velocity × time) is central to solving this problem. By calculating the winner's speed using her distance and time, one can determine how far the second-place runner has traveled within the same time interval, and thereby compute the gap between them.

Uniform Motion

This concept involves the idea that an object moving at a constant velocity covers equal distances in equal intervals of time. In problems like this, where it is assumed that each runner maintains a constant speed, the linear relationship between speed, distance, and time can be applied directly.

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