Question
In a balanced three-phase wye-delta system, the impedance per phase of the load is $21+j 9 \Omega$ and the source voltage is $\mathbf{V}_{a b}=120 \sqrt{3} \angle 60^{\circ} \mathrm{V}$ rms. If the line impedance is $1+j 1 \Omega$, determine the line currents.
Step 1
We have the load impedance per phase \( Z_L = 21 + j9 \, \Omega \), the source voltage \( V_{ab} = 120 \sqrt{3} \angle 60^{\circ} \, \text{V} \), and the line impedance \( Z_{line} = 1 + j1 \, \Omega \). Show more…
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