00 \times 10^{-5} \mathrm{~m}$, the wavelength of the light (lambda) as $500$ nm or $500 \times 10^{-9} \mathrm{~m}$, and the distance from the slits to the screen (capital D) as $1.00 \mathrm{~m}$. We are asked to find the distance between the $m=1$ and $m=3$
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