Question
In a given diffusion apparatus, 15.0 mL of HBr gas diffused in 1.0min. In the same apparatus and under the same conditions, 20.3mL of an unknown gas diffused in 1.0 min. The unknown gas is a hydrocarbon. Find its molecular formula.
Step 1
According to Graham's law of diffusion, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass. This can be written as: \[ \frac{D_{HBr}}{D_{unknown}} = \sqrt{\frac{M_{unknown}}{M_{HBr}}} \] Show more…
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In a given diffusion apparatus, 15.0 $\mathrm{mL}$ of HBr gas diffuses in 1.0 $\mathrm{min}$ . In the same apparatus and under the same conditions, 20.3 $\mathrm{mL}$ of an unknown gas diffuses in 1.0 $\mathrm{min}$ . The unknown gas is a hydrocarbon. Find its molecular formula.
In a given diffusion apparatus, 150 mL of HBr gas (molar mass = 80.91 g/mol) diffused in 10 min. In the same apparatus and under same conditions, 223 mL of an unknown gas diffused in 10 min. What is the molar mass of the unknown gas? A) 51.2 g/mol B) 31.8 g/mol C) 36.6 g/mol D) 44.2 g/mol E) 57.1 g/mol
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