00:01
In problem 15 we have 50 light bulbs at which two are bad.
00:05
Then we have 50 containing two bad bulbs and 48 good.
00:15
An inspector examines five bulbs by choosing five at random and without replacement, which means the number of combinations to select five out of the 50 is 50 choose five.
00:31
This is the total number of combinations for our problem.
00:37
For part a, we want to find the probability that at least one defective bulb or one bad bulb is selected among the five.
00:48
The probability that at least one is bad.
00:55
This means one is bad or two is bad or three is bad, four is bad or five is bad.
01:03
Instead of calculating these 5 probabilities and add them together, we just get the complement event.
01:14
This probability equals 1 minus the probability for the complement event of at least 1 one which is none is bad.
01:27
This is the complement event for at least 1 is bit.
01:35
To get the probability we divide by the total number of combinations which is 50 to 6.
01:40
Five and determine the number of combinations to have none is bad.
01:50
None is bad means that the five is good the five selected are good means we want to choose 48 we want to choose 5 out of 48 then it's 48 it choose 5...