In a $p-n-p$ transistor circuit, the collector current is $10 \mathrm{~mA}$. If $90 \%$ of the holes emitted from emitter reach the collector;
(a) the emitter current will be $9 \mathrm{~mA}$
(b) the emitter current will be $11 \mathrm{~mA}$
(c) the base current will be $1 \mathrm{~mA}$
(d) the base current will be $-1 \mathrm{~mA}$