In adiabatic demagnetization, we use a magnetic field to couple away almost all of the residual energy of a crystal that has been cooled to 2.2 K by liquid helium. (We can get below the normal boiling point of liquid helium by boiling it at lower pressure.) Use Einstein's molar energy of the crystal,
$$
E_{\mathrm{m}}=3 \mathcal{N}_A\langle\varepsilon\rangle_{\mathrm{vib}}=\frac{3 \mathcal{N}_A \omega_E}{e^{\omega / /\left(k_{\mathrm{B}} T\right)}-1}
$$
in the low-temperature limit to estimate the residual molar energy of a crystal with an Einstein frequency of $105 \mathrm{~cm}^{-1}$ at 2.2 K . (The answer is smaller than you may expect.)