00:02
All right, so in this problem, we have the lrc series circuit, and we know r, l, and c, and also we know the current amplitude.
00:11
So for part a, what is the voltage amplitude of the source? so, yeah, we also know that this is at the resonant frequency.
00:23
So in this case, in this case, the impedance of the circuit equal to r.
00:29
So the voltage amplitude will be equal to i times r, which equal to 150 volts.
00:42
And for part b, what is the amplitude of the body across the resistor, inductor, and the capacitor? well, so vr, which means the body across the resistor, is simply i times r, as we found here.
01:01
So equal to 150 volts.
01:05
And a vl equal to i times the reactance of the inductor, which is omega -l.
01:16
Because in the resonant case, omega -l equal to 1 over omega -c.
01:23
So we can solve for omega -equal equal to 1 -square -root, 1 -square -route -l -c.
01:34
So this is the angular frequency at the resonance case...